《Python语言程序设计》 第6章编程题答案（6.1~6.10）

wg19830119

6.1:打印“五角数”

def getPentahonalNumber(n):

   for i in range(1,n):

       number=int(i * ( 3 * i - 1) / 2)

       print(format(number,'5d'),end='\t')

       if i % 10 == 0:

            print()

getPentahonalNumber(100)

6.2:n的每位数相加：

def sumDigits(n):

   sum=0

   count=0

   while n != 0:

       number=n % 10

       sum+=number

       n= n // 10

       count+=1

   return sum , count

def main(n):

   sum,count=sumDigits(n)

   print('every digit sum is '+str(sum))

   print(str(n)+' is '+str(count)+'bits digit')

main(n=eval(input('n=')))

6.3:判断是否是回文数：

def reverse(number):

   if isPalindrome(number)==number:

       print(str(number)+'is palindrome')

   else:

       print(str(number)+'is not palindrome')

def isPalindrome(number):

   count=0

   n=''

   while number != 0:

       n=n+str(number % 10)

       number=number // 10

       count+=1

   new_number=int(n)

   return new_number

reverse(number=eval(input('enter an integer:')))

6.4：输出反转数：

def reverse(number):

   n=''

   while number != 0:

       n=n+str(number % 10)  

       number=number // 10

       new_number=int(n)

   return new_number

print('the reverse number is ',reverse

(number=eval(input('enter an integer:'))))

6.5三个数从小到大排列：

def displaySortedNumbers(num1,num2,num3):

   if num1 > num2:

       num1,num2=num2,num1

   if num2 > num3:

       num2,num3=num3,num2

   if num1 > num2:

       num1,num2=num2,num1

   return num1,num2,num3

num1,num2,num3=eval(input('enter three numbers:'))

print(displaySortedNumbers(num1,num2,num3))

6.6：

def displayPattern(n):

   for i in range(1,n+1):

       for j in range(n-i,0,-1):

            print(' ',end='')

       for j in range(i,0,-1):

            print(j,end='')

       print()

displayPattern(eval(input('enter an integer:')))

6.7：

def futureInvestmentValue(investmentAmount,monthlyInterestRate,years):

   value=investmentAmount*(1+monthlyInterestRate)**(years*12)

   return value

def main(investmentAmount,monthlyInterestRate,years):

   print('Years   Future Value')

   for i in range(1,years+1):

       print(format(i,'5d')+'\t',end='')

       print(format(futureInvestmentValue(investmentAmount,monthlyInterestRate,i),'.2f'))

Amount=eval(input('enter the amount invested:'))

monthlyrate=eval(input('enter the interest rate:'))

years=eval(input('enter the interest years:'))

main(Amount,monthlyrate,years)

   

6.8:

def celsiusToFahrenheit(celsius):

   fahrenheit=(9/5)*celsius+32

   return round(fahrenheit,1)

def fahrenheitToCelsius(fahrenheit):

   celsius=(5/9)*(fahrenheit-32)

   return round(celsius,2)

def title():

   print('-'*70)

   print('   celsius    |    fahrenheit    ||   fahrenheit    |    celsius')

   print('-'*70)

def main():

   title()

   j=120

   for i in range(40,30,-1):

       print(format(float(i),'^12.1f'),'\t',end='')

       print(format(celsiusToFahrenheit(i),'^12.1f'),end='')

       print(format(float(j),'^12.1f'),'\t',end='')

       print(fahrenheitToCelsius(j))

       j-=10

main()

6.9:

略

6.10:

def isprime(number):

   isprime=True

   i=2

   while i < number:

       if number % i ==0:

            isprime=False

       i+=1

   return isprime

count=0

for i in range(2,10001):

   if isprime(i):

       #print(format(i,'5d'),end='')

       count+=1

       #ifcount % 10==0:

            #print()

print(count)

albtb123

我也来顶一下..

Lowell

向楼主学习

sgfb

发发呆，回回帖，工作结束~

huiming

佩服佩服！